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8x^2+5=76
We move all terms to the left:
8x^2+5-(76)=0
We add all the numbers together, and all the variables
8x^2-71=0
a = 8; b = 0; c = -71;
Δ = b2-4ac
Δ = 02-4·8·(-71)
Δ = 2272
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2272}=\sqrt{16*142}=\sqrt{16}*\sqrt{142}=4\sqrt{142}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{142}}{2*8}=\frac{0-4\sqrt{142}}{16} =-\frac{4\sqrt{142}}{16} =-\frac{\sqrt{142}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{142}}{2*8}=\frac{0+4\sqrt{142}}{16} =\frac{4\sqrt{142}}{16} =\frac{\sqrt{142}}{4} $
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